Checking out my manual, camber specification is 1/2 degree+/- 1/2 degree with the vehicle loaded (2 person + 130 pounds of luggage for spiders '75 on).
I cut down a yardstick to use as a straightedge. Then fastened this to a framer's square that has a small built in level. The driver's tire is positive camber of 1 degree (unloaded) and the passenger's tire is slightly less. I doubt my eye is keen enough to see this
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, more likely an illusion having to do with the lines of the car.
My geometry is a bit rough and I can't find my scientific calculator...but the internet has all the answers
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My tire rim is 14.3125 inches (14 5/16) bead to bead. This is the hypotenuse of a right triangle when the straight edge is vertical. The bottom leg of the triangle is the distance the straightedge had to be pushed out from the bottom bead..that distance was .25 (1/4 inch). The sine of an angle is opposite/hypotenuse. In this case .25/14.3125 = 0.0175. Going to a sine chart, this is 1degree.
Even if I measured incorrectly and compound my errors by 1/16 of an inch............5/16 divided by 14 1/4 results in an increase in camber of less than 1/2 degree. Since these measurements were done with the vehicle empty and I am on the outside limits of specifications,,,,,I'll call it good-to-go
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